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JEE Mains · Maths · STD 11 - 8. sequence and series

श्रेणी \(\frac{3}{1^{2} \times 2^{2}}+\frac{5}{2^{2} \times 3^{2}}+\frac{7}{3^{2} \times 4^{2}}+\ldots .\) के 10 पदों का योग है

  1. A \(1\)
  2. B \(\frac{120}{121}\)
  3. C \(\frac{99}{100}\)
  4. D \(\frac{143}{144}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{120}{121}\)

Step-by-step Solution

Detailed explanation

\(S=\frac{2^{2}-1^{2}}{1^{2} \times 2^{2}}+\frac{3^{2}-2^{2}}{2^{2} \times 3^{2}}+\frac{4^{2}-3^{2}}{3^{2} \times 4^{2}}+\ldots\)…
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