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JEE Mains · Maths · STD 12 - 11. three dimension geometry

रेखाएँ \(x = ay -1= z -2\) तथा \(x =3 y -2= bz -2\), \(( ab \neq 0)\) समतलीय हैं, यदि 

  1. A \(b=1, a \in R-\{0\}\)
  2. B \(a=2, b=3\)
  3. C \(a=2, b=2\)
  4. D \(a=1, b \in R-\{0\}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(b=1, a \in R-\{0\}\)

Step-by-step Solution

Detailed explanation

\(\frac{x+1}{a}=y=\frac{z-1}{a}\) \(\frac{x+2}{3}=y=\frac{z}{3 / b}\) lines are Co-planar \(\left|\begin{array}{ccc}a & 1 & a \\ 3 & 1 & \frac{3}{b} \\ -1 & 0 & -1\end{array}\right|=0 \Rightarrow-\left(\frac{3}{b}-a\right)-1(a-3)=0\) \(a-\frac{3}{b}-a+3=0\) \(b=1, a \in R-\{0\}\)
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