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JEE Mains · Maths · STD 12 - 10. vector algebra

माना तीन सदिश \(\vec{a}, \vec{b}\) तथा \(\vec{c}\) इस प्रकार हैं कि \(\overrightarrow{ c }\), सदिशों \(\overrightarrow{ a }\) तथा \(\overrightarrow{ b }\) के समतल में है, \(\overrightarrow{ a } \cdot \overrightarrow{ c }=7\) है तथा \(\overrightarrow{ b }\), सदिश \(\overrightarrow{ c }\) के लम्बवत है, जबकि \(\vec{a}=-\hat{i}+\hat{j}+\hat{k}\) तथा \(\overrightarrow{ b }=2 \hat{i}+\hat{k}\) हैं, तो \(2|\vec{a}+\vec{b}+\vec{c}|^{2}\) बराबर है ......... |

  1. A \(75\)
  2. B \(50\)
  3. C \(80\)
  4. D \(100\)
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Answer & Solution

Correct Answer

(A) \(75\)

Step-by-step Solution

Detailed explanation

Let \(\overrightarrow{ c }=\lambda(\overrightarrow{ b } \times(\overrightarrow{ a } \times \overrightarrow{ b }))\) \(=\lambda((\overrightarrow{ b } \cdot \overrightarrow{ b }) \overrightarrow{ a }-(\overrightarrow{ b } \cdot \overrightarrow{ a }) \overrightarrow{ b })\)…
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