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JEE Mains · Maths · STD 12 - 11. three dimension geometry

माना समतल, समतलों \(P 1: x+(\lambda+4) y+z=1 \) तथा  P2: \(2 x+y+z=2\) की प्रतिच्छेदी रेखा पर स्थित है जो बिन्दु \((0,1,0)\) तथा \((1,0,1)\) से गुजरता है। तब समतल \(\mathrm{P} 2\) से बिन्दु \((2 \lambda, \lambda,-\lambda)\) की दूरी है

  1. A \(5 \sqrt{6}\)
  2. B \(4 \sqrt{6}\)
  3. C \(2 \sqrt{6}\)
  4. D \(3 \sqrt{6}\)
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Answer & Solution

Correct Answer

(D) \(3 \sqrt{6}\)

Step-by-step Solution

Detailed explanation

Equation of plane passing through point of intersection of \(P 1\) and \(P 2\) \(P = P 1+ kP 2\) \(( x +(\lambda+4) y + z -1)+ k (2 x + y + z -2)=0\) Passing through \((0,1,0)\) and \((1,0,1)\) \((\lambda+4-1)+ k (1-2)=0\) \((\lambda+3)- k =0\) Also passing \((1,0,1)\)…
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