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JEE Mains · Maths · STD 12 - 9. differential equations

माना अवकल समीकरण \(xdy - ydx =\sqrt{\left( x ^{2}- y ^{2}\right)}\) \(dx , x \geq 1\) का हल \(y = y ( x )\) है तथा \(y (1)=0\) है। यदि रेखाओं \(x =1, x = e ^{\pi}, y =0\) तथा \(y = y ( x )\) द्वारा घिरे क्षेत्र का क्षेत्रफल \(\alpha e ^{2 \pi}+\beta\) है, तो \(10(\alpha+\beta)\) का मान बराबर है

  1. A \(6\)
  2. B \(2\)
  3. C \(4\)
  4. D \(0\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(4\)

Step-by-step Solution

Detailed explanation

\(x d y-y d x=\sqrt{x^{2}-y^{2}} d x\) \(\Rightarrow \frac{x d y-y d x}{x^{2}}=\frac{1}{x} \sqrt{1-\frac{y^{2}}{x^{2}}} d x\) \(\Rightarrow \int \frac{d\left(\frac{y}{x}\right)}{\sqrt{1-\left(\frac{y}{x}\right)^{2}}}=\int \frac{d x}{x}\)…
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