ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

माना \(A=\left[\begin{array}{cc}\frac{1}{\sqrt{2}} & -2 \\ 0 & 1\end{array}\right]\) और \(P=\left[\begin{array}{cc}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta\end{array}\right], \theta\gt0\). यदि \(\mathrm{B}=\mathrm{PAP}^{\mathrm{T}}, \mathrm{C}=\mathrm{P}^{\mathrm{T}} \mathrm{B}^{10} \mathrm{P}\) तथा \(C\) के विकर्णों के अवयवों का योग \(\frac{\mathrm{m}}{\mathrm{n}}\), जहाँ \(\operatorname{gcd}(\mathrm{m}, \mathrm{n})=1\), तो \(\mathrm{m}+\mathrm{n}\) :

  1. A \(127\)
  2. B \(258\)
  3. C \(65\)
  4. D \(2049\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(65\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \mathrm{P}=\left[\begin{array}{cc} \cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{array}\right] \\ & \because \mathrm{P}^{\mathrm{T}} \mathrm{P}=\mathrm{I} \\ & \mathrm{~B}=\mathrm{PAPT} \end{aligned}\) Pre multiply by…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app