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JEE Mains · Maths · STD 11 - 8. sequence and series

माना \(\frac{1}{x_{1}}, \frac{1}{x_{2}}, \ldots, \frac{1}{x_{ n }}(i=1,2, \ldots, n\) के लिए \(x_{i} \neq 0\) है) समांतर श्रेढ़ी में ऐसे हैं कि \(x_{1}=4\) तथा \(x_{21}=20\) है। यदि \(n\) का न्यूनतम धनपूर्णांक मान जिसके लिए \(x_{ n } >50\) है, तो \(\sum_{i=1}^{ n }\left(\frac{1}{x_{i}}\right)\) बराबर है

  1. A \(3\)
  2. B \(\frac {13}{8}\)
  3. C \(\frac {13}{4}\)
  4. D \(\frac {1}{8}\)
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Answer & Solution

Correct Answer

(C) \(\frac {13}{4}\)

Step-by-step Solution

Detailed explanation

\(\because\) \(\frac{1}{{{x_1}}},\frac{1}{{{x_2}}},\frac{1}{{{x_3}}},....,\frac{1}{{{x_n}}}\) are in \(A.P.\) \({x_1} = 4\,\,\,\,\,{x_{21}} = 20\) Let \('d'\) be the common difference of this \(A.P.\) \(\therefore \) its \({21^{st}}\) term…
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