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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

मान \(\alpha, \beta\) समीकरण \(x ^{2}+(20)^{1 / 4} x +(5)^{1 / 2}=0\) के दो मूल हैं। तो \(\alpha^{8}+\beta^{8}\) बराबर है

  1. A \(10\)
  2. B \(50\)
  3. C \(160\)
  4. D \(100\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(50\)

Step-by-step Solution

Detailed explanation

\(\left(x^{2}+\sqrt{5}\right)^{2}=\sqrt{20} x^{2}\) \(x^{4}=-5 \Rightarrow x^{8}=25\) \(\alpha^{8}+\beta^{8}=50\)
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