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JEE Mains · Maths · STD 11 - 12. limits

\(\mathop {{\rm{lim}}}\limits_{x \to 0} \frac{{{\rm{sin}}\left( {\pi {{\cos }^2}x} \right)}}{{{x^2}}}\) का मान है:

  1. A \( - \pi \)
  2. B \(\;\pi \)
  3. C \(\frac{\pi }{2}\)
  4. D \(1\)
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Answer & Solution

Correct Answer

(B) \(\;\pi \)

Step-by-step Solution

Detailed explanation

\(\mathop {lim}\limits_{x \to 0} \frac{{\sin \left( {\pi {{\cos }^2}x} \right)}}{{{x^2}}}\) \( = \mathop {lim}\limits_{x \to 0} \frac{{\sin \left( {\pi \left( {1 - {{\sin }^2}x} \right)} \right)}}{{{x^2}}}\)…
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