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JEE Mains · Maths · STD 12 - 11. three dimension geometry

एक समतल \(P\) में, समतलों \(\overrightarrow{\mathrm{r}} \cdot(\hat{\mathrm{i}}+\hat{\mathrm{j}}+\hat{\mathrm{k}})=6\) तथा \(\overrightarrow{\mathrm{r}} \cdot(2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}+4 \hat{\mathrm{k}})=-5\) की प्रतिच्छेदन रेखा स्थित है। यदि \(\mathrm{P}\), बिंदु \((0,2,-2)\) से होकर जाता है, तो बिंदु \((12,12,18)\) की समतल \(\mathrm{P}\) से दूरी का वर्ग है

  1. A \(1240\)
  2. B \(620\)
  3. C \(310\)
  4. D \(155\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(620\)

Step-by-step Solution

Detailed explanation

Equation of plane \(P\) is \((x+y+z-6)+\lambda(2 x+3 y+4 z+5)=0\) Plane passes through the point \((0,2,-2)\) \(\therefore(2-2-6)+\lambda(6-8+5)=0\) \(-6+\lambda(3)=0\) \(\lambda=2\) Equation of plane \(p\) is \((x+y+z-6)+2(2 x+3 y+4 z+5)=0\) \(5 x+7 y+9 z+4=0\)…
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