\(Ti ^{2+}, V ^{2+}, Ti ^{3+}\) तथा \(Sc ^{3+}\) के जलयोजित आयनों पर विचार कीजिये । उनके स्पिन-मात्र चुम्बकीय आघूर्णों का सही क्रम है

A \(Ti^{3+} < T^{2+} < Sc^{3+} < V^{2+}\)
B \(Sc^{3+} < Ti^{3+} < Ti^2 < V^{2+}\)
C \(V^{2+} < Ti^{2+} < Ti^{3+} < Sc^{3+}\)
D \(Sc^{3+} < Ti^{3+} < V^{2+} < Ti^{2+}\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(Sc^{3+} < Ti^{3+} < Ti^2 < V^{2+}\)

Step-by-step Solution

Detailed explanation

\(T{i^{ + 2}}\, = \,1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,3{d^2}\) unpaired electron \(=\,2\) spin only magnetic moment \((\mu )\, = \,\sqrt {2(2 + 2)} \, = \,\sqrt 8 \,B.M\) \(T{i^{ + 3}}\, = \,1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,3{d^1}\) unpaired electron \(=\,1\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

सूची-I का सूची-II से सुमेलित करें

सूची-I (रेडॉक्स अभिक्रिया)	सूची-II (रेडॉक्स अभिक्रिया का प्रकार)
(A) CH_4(g) + 2O_2(g) → CO_2(g) + 2H₂O_(l)	(I) विसमानुपातन अभिक्रिया
(B) 2NaH_(s) → 2Na_(s) + H_2(g)	(II) संयोजन अभिक्रिया
(C) V₂O_5(s) + 5Ca_(s) → 2V_(s) + 5CaO_(s)	(III) अपघटन अभिक्रिया
(D) 2H₂O_2(aq) → 2H₂O_(l) + O_2(g)	(IV) विस्थापन अभिक्रिया

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