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JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry

परमाणु क्रमांक 24 के एक तत्व के लिए सामान्य धनात्मक ऑक्सीकरण अवस्थायें है 

  1. A \(+2\) से \(+6\)
  2. B \(+1\) तथा \(+3\) से \(+6\)
  3. C \(+1\) तथा \(+3\)
  4. D \(+1\) से \(+6\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(+2\) से \(+6\)

Step-by-step Solution

Detailed explanation

\(\operatorname{Cr}\,(Z=24)\) \([ Ar ]\, 4 s ^{1}\, 3 d ^{5}\, Cr\) shows common oxidation states starting from \(+2\) to \(+6\)
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