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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

एथीन के पूर्ण दहन के लिए \(\mathrm{C}_2 \mathrm{H}_4(\mathrm{~g})+3 \mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{CO}_2(\mathrm{~g})+2 \mathrm{H}_2 \mathrm{O}(\mathrm{l})\) \(300 \mathrm{~K}\) बम केलोरीमीटर मे मापी गयी उष्मा \(1406 \mathrm{~kJ} \mathrm{~mol}^{-1}\) है। साम्यावस्था पर पहुंचने हेतु \(\mathrm{T} \Delta \mathrm{S}\) की न्युनतम मात्र है (-) _ \(\mathrm{kJ}\) (निकटतम पूर्णांक में) दिया गया है : \(\mathrm{R}=8.3 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\)

  1. A \(1411\)
  2. B \(1412\)
  3. C \(1413\)
  4. D \(1414\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1411\)

Step-by-step Solution

Detailed explanation

\(C _2 H _{4( g )}+3 O _{2( g )} \longrightarrow 2 CO _{2( g )}+2 H _2 O_{(l)}\) \(\Delta U =-1406\,KJ\,mol ^{-1}, T =300\,K\) \(\Delta H =\Delta U +\Delta n _{ g } RT\) \(\Delta H =-1406+(-2) \times 8.3 \times 300=-1406-4.98\) \(=-1410.98\,KJ\,mol ^{-1} \approx-1411\)…
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