एक बंद U-ट्यूब में 264 mL ऑक्सीजन के साथ मिलाने पर एक हाइड्रोकार्बन के 80 mL का पूर्ण दहन होता है। 273 K तक ठंडा करने के बाद अवशिष्ट गैसें 224 mL आयतन घेरती हैं। जब निकाय को KOH विलयन से उपचारित किया जाता है, तो आयतन घटकर 64 mL हो जाता है। हाइड्रोकार्बन का सूत्र है:

A \( C_{2}H_{4} \)
B \( C_{4}H_{10} \)
C \( C_{2}H_{2} \)
D \( C_{2}H_{6} \)

Verified Solution

Answer & Solution

Correct Answer

(C) \( C_{2}H_{2} \)

Step-by-step Solution

Detailed explanation

\(C _{ x } H _{ y ( g )}+\left( x +\frac{ y }{4}\right) O _{2(g)} \longrightarrow xCO _{2(g)}+\frac{ y }{2} H _2 O _{(\ell)}\) \(\begin{array}{lllll} t =0 & 80 & 264 & 0\end{array}-\) \(t = t _{\text {final }} \quad-\quad 264-80\left( x +\frac{ y }{4}\right) \quad 80 x\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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