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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

\(0.1\, M\, H _{2} SO _{4}\) के \(20\, mL\) विलयन को \(0.2\, M\, NH _{4} OH\) के \(30\, mL\) विलयन के साथ मिलाया गया तब परिणामी विलयन की \(pH\) की गणना कीजिए। ( दिया गया है \(NH _{4} OH\) का \(\left.pK _{ b }=4.7\right)\)

  1. A \(5.2\)
  2. B \(9\)
  3. C \(5\)
  4. D \(9.4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(9\)

Step-by-step Solution

Detailed explanation

\(\mathop {\mathop {{H_2}S{O_4}}\limits_{2\,m.m} }\limits_ - + \mathop {\mathop {2N{H_4}OH}\limits_{6\,m.m} }\limits_{2\,m.m} \to \mathop {{{(N{H_4})}_2}S{O_4}}\limits_{2\,m.m} + 2{H_2}O\) \(pOH = 4.7 + \log \frac{4}{2} = 5\) \(pH = 14 - 5 = 9\)
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