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JEE Mains · Maths · STD 12 - 7.2 definite integral

The value of the integral  \(\int\limits_4^{10} {\frac{{\left[ {{x^2}} \right]dx}}{{\left[ {{x^2} - 28x + 196} \right] + \left[ {{x^2}} \right]}}}\) મેળવો. [ કે જ્યાં  \(\left[ x \right]\) મહતમ પૃણાંક છે .]

  1. A \(\frac{1}{3}\)
  2. B \(6\)
  3. C \(7\)
  4. D \(3\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(3\)

Step-by-step Solution

Detailed explanation

\(I = \int\limits_4^{10} {\frac{{\left[ {{x^2}} \right]}}{{\left[ {{x^2} - 28x + 196} \right] + \left[ {{x^2}} \right]}}} dx\).......\((1)\) \({\rm{Use}}\int\limits_a^b {f\left( {a + b - x} \right)} dx = \int\limits_a^b {f\left( x \right)dx} \)…
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