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JEE Mains · Maths · STD 11 - 8. sequence and series

જો \(a_1, a_2, a_3, …….\) એ સમાંતર શ્રેણીમાં છે કે જેથી \(a_1 + a_7 + a_{16} = 40\), હોય તો પ્રથમ \(15\) પદનો સરવાળો મેળવો.

  1. A \(200\)
  2. B \(280\)
  3. C \(150\)
  4. D \(120\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(200\)

Step-by-step Solution

Detailed explanation

\({a_1},{a_2},....{a_n}\) are in A.P. \({a_1} + {a_7} + {a_{16}} = 40\) \( \Rightarrow a + a + 6d + a + 15d = 40\) \( \Rightarrow 3a + 21d = 40\) \( \Rightarrow a + 7d = \frac{{40}}{3}\) \(515 = \frac{{15}}{2}\left[ {2a + 14d} \right]\) \( = 15\left[ {a + 7d} \right]\)…
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