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JEE Mains · Maths · STD 11 - Trigonometrical equations

સમીકરણ \(8\cos x \cdot \left( {\cos \left( {\frac{\pi }{6} + x} \right) \cdot \cos \left( {\frac{\pi }{6} - x} \right) - \frac{1}{2}} \right) = 1\) નાં અંતરાલ \(\left[ {0,\pi } \right]\) માં તમામ ઉકેલોની સરવાળો જો \(k\pi \) હોય તો \(k = \;.\;.\;.\) .

  1. A \(\frac{{13}}{9}\)
  2. B \(\frac{8}{9}\)
  3. C \(\frac{{20}}{9}\)
  4. D \(\frac{2}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{{13}}{9}\)

Step-by-step Solution

Detailed explanation

\(8 \cos x\left\{\cos \left(\frac{\pi}{6}+x\right) \cdot \cos \left(\frac{\pi}{6}-x\right)-\frac{1}{2}\right\}=1\) \(\Rightarrow 4 \cos x\left\{2 \cos \left(\frac{\pi}{6}+x\right) \cos \left(\frac{\pi}{6}-x\right)-1\right\}=1\)…
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