ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 11. three dimension geometry

રેખા \(l_1\) એ \(О\) બિંદુ \((2,6,2)\) માંથી. પસાર થાય છે તથા સમતલ \(2 x+y-2 z=10\)ને લંબ છે.તો રેખા \(l_1\) અને રેખા \(\frac{x+1}{2}=\frac{y+4}{-3}=\frac{z}{2}\) વચ્ચેનું લઘુતમ અંતર \(..........\) છે.

  1. A \(7\)
  2. B \(\frac{19}{3}\)
  3. C \(\frac{19}{3}\)
  4. D \(9\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(9\)

Step-by-step Solution

Detailed explanation

Line \(\ell\), is given by \(L_1: \frac{x-2}{2}=\frac{y-6}{1}=\frac{z-2}{-2}\) Given, \(L _2: \frac{ x +1}{2}=\frac{ y +4}{-3}=\frac{ z }{2}\) \(\text { Shortest distance }=\left|\frac{\overline{ AB } \cdot \overline{ MN }}{ MN }\right|\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app