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JEE Mains · Maths · STD 11 - 4.1 complex nubers

જો \(z=\frac{\sqrt{3}}{2}+\frac{i}{2}, i=\sqrt{-1}\) હોય, તો \(\left(z^{201}-i\right)^8=\) ___ .

  1. A -1
  2. B 0
  3. C 1
  4. D 256
Verified Solution

Answer & Solution

Correct Answer

(D) 256

Step-by-step Solution

Detailed explanation

\(z=\cos \frac{\pi}{6}+i \sin \frac{\pi}{6}\) \(z^{201}=\cos \left(201 \frac{\pi}{6}\right)+i \sin \left(201 \frac{\pi}{6}\right)=-i\) \(\left(z^{201}-i\right)^8=(-2 i)^8=256\)
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