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JEE Mains · Maths · STD 11- 2. Relation and Function

જો વિધેય \(f(x)=\sqrt{x}\) અને \(g ( x )=\sqrt{1- x }\) આપેલ છે તો આપેલ વિધેયો \(f+g, f-g, f / g, g / f, g-f\) નો સામાન્ય પ્રદેશ મેળવો કે જ્યાં \((f \pm g)(x)=\) \(f(x) \pm g(x),(f / g)(x)=\frac{f(x)}{g(x)}\) દર્શાવે છે.

  1. A \(0 \leq x \leq 1\)
  2. B \(0 \leq x< 1\)
  3. C \(0< x< 1\)
  4. D \(0< x \leq 1\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(0< x< 1\)

Step-by-step Solution

Detailed explanation

\(f(x)+g(x)=\sqrt{x}+\sqrt{1-x},\) domain \([0,1]\) \(f(x)-g(x)=\sqrt{x}-\sqrt{1-x},\) domain \([0,1]\) \(g(x)-f(x)=\sqrt{1-x}-\sqrt{x},\) domain \([0,1]\) \(\frac{f(x)}{g(x)}=\frac{\sqrt{x}}{\sqrt{1-x}},\) domain \([0,1)\) \(\frac{g(x)}{f(x)}=\frac{\sqrt{1-x}}{\sqrt{x}},\)…
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