JEE Mains · Maths · STD 11- 2. Relation and Function
If the functions are defined as \(f(x)=\sqrt{x}\) and \(g ( x )=\sqrt{1- x },\) then what is the common domain of the following functions: \(f+g, f-g, f / g, g / f, g-f\) where \((f \pm g)(x)=\) \(f(x) \pm g(x),(f / g)(x)=\frac{f(x)}{g(x)}\)
- A \(0 \leq x \leq 1\)
- B \(0 \leq x< 1\)
- C \(0< x< 1\)
- D \(0< x \leq 1\)
Answer & Solution
Correct Answer
(C) \(0< x< 1\)
Step-by-step Solution
Detailed explanation
\(f(x)+g(x)=\sqrt{x}+\sqrt{1-x},\) domain \([0,1]\) \(f(x)-g(x)=\sqrt{x}-\sqrt{1-x},\) domain \([0,1]\) \(g(x)-f(x)=\sqrt{1-x}-\sqrt{x},\) domain \([0,1]\) \(\frac{f(x)}{g(x)}=\frac{\sqrt{x}}{\sqrt{1-x}},\) domain \([0,1)\) \(\frac{g(x)}{f(x)}=\frac{\sqrt{1-x}}{\sqrt{x}},\)…
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