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JEE Mains · Maths · STD 11 - Trigonometrical equations

જો \(sin \,3x\, = cos\, 2x\) હોય તો અંતરાલ \(\left( {\frac{\pi }{2},\pi } \right)\) માં ઉકેલોની સંખ્યા મેળવો.

  1. A \(3\)
  2. B \(4\)
  3. C \(2\)
  4. D \(1\)
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Answer & Solution

Correct Answer

(D) \(1\)

Step-by-step Solution

Detailed explanation

Given \(\sin \,3x\, = \,\cos 2x\) \( \Rightarrow {\kern 1pt} \sin \,3x\, = \,\sin \,(\pi /2 - 2x)\) We now that \(\sin A = \sin B\) \( \Rightarrow \,A\, = \,n\pi + {( - )^n}B,\) where \(n\) is an integer Using the above identity , we get…
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