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JEE Mains · Maths · STD 11 - 8. sequence and series

જો શ્રેણી \(\frac{1}{5}+\frac{2}{65}+\frac{3}{325}+\frac{4}{1025}+\frac{5}{2501}+\ldots\) ના પ્રથમ દસ પદ્દોનો સરવાળો \(\frac{ m }{ n }\) છે, જ્યાં \(m\) અને \(n\) પ૨સ્પર અવિભાજય  સંખ્યાઓ છે, તો  \(m + n =\dots\dots\dots\)

  1. A \(280\)
  2. B \(277\)
  3. C \(276\)
  4. D \(272\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(276\)

Step-by-step Solution

Detailed explanation

\(\frac{1}{5}+\frac{2}{65}+\frac{3}{325}+\frac{4}{1025}+\frac{5}{2501}+\ldots \ldots\) \(T_{n}=\frac{n}{4 n^{4}+1}\) \(=\frac{ n }{\left(2 n^{2}+1\right)^{2}-(2 n )^{2}}=\frac{ n }{\left(2 n ^{2}+2 n +1\right)\left(2 n ^{2}-2 n +1\right)}\)…
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