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JEE Mains · Maths · STD 11 - 9. straight line

જો રેખા \(2 x-y+3=0\) રેખાઓ \(4 x-2 y+\alpha=0\) અને \(6 x-3 y+\beta=0\) થી અંતર અનુક્રમે \(\frac{1}{\sqrt{5}}\) અને \(\frac{2}{\sqrt{5}}\) હોય તો \(\alpha\) અને \(\beta\) is ની શક્ય કિમતોનો સરવાળો ......... થાય 

  1. A \(12\)
  2. B \(30\)
  3. C \(18\)
  4. D \(60\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(30\)

Step-by-step Solution

Detailed explanation

Apply distance between parallel line formula \(4 x-2 y+\alpha=0\) \(4 x-2 y+6=0\) \(\left|\frac{\alpha-6}{255}\right|=\frac{1}{55}\) \(|\alpha-6|=2 \Rightarrow \alpha=8,4\) \(\operatorname{sum}=12\) again \(6 x-3 y+\beta=0\) \(6 x-3 y+9=0\)…
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