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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

જો \(A = \left[ {\begin{array}{*{20}{c}}2&{ - 3}\\{ - 4}&1\end{array}} \right],\) તો \(adj\;\left( {3{A^2} + 12A} \right) = \) . . . .

  1. A \(\left[ {\begin{array}{*{20}{c}}{72}&{ - 63}\\{ - 84}&{51}\end{array}} \right]\)
  2. B \(\left[ {\begin{array}{*{20}{c}}{72}&{ - 84}\\{ - 63}&{51}\end{array}} \right]\)
  3. C \(\left[ {\begin{array}{*{20}{c}}{51}&{63}\\{84}&{72}\end{array}} \right]\)
  4. D \(\left[ {\begin{array}{*{20}{c}}{51}&{84}\\{63}&{72}\end{array}} \right]\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\left[ {\begin{array}{*{20}{c}}{51}&{63}\\{84}&{72}\end{array}} \right]\)

Step-by-step Solution

Detailed explanation

We have \(A = \left[ {\begin{array}{*{20}{c}} 2&{ - 3}\\ { - 4}&1 \end{array}} \right]\) \( \Rightarrow {A^2} = \left[ {\begin{array}{*{20}{c}} {16}&{ - 9}\\ { - 12}&{13} \end{array}} \right]\)…
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