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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

ધારોકે \(\alpha, \beta\) એ દ્વિઘાત સમીકરણ \(12 x^2-20 x+3 \lambda=0, \lambda \in Z\) ના બીજ છે. જો \(\frac{1}{2} \leqslant|\beta-\alpha| \leqslant \frac{3}{2}\) હોય, તો \(\lambda\) ની તમામ શક્ય કિંમતોનો સરવાળો ___ છે.

  1. A 6
  2. B 1
  3. C 3
  4. D 4
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Answer & Solution

Correct Answer

(C) 3

Step-by-step Solution

Detailed explanation

\(\frac{1}{2} \leq|\alpha-\beta| \leq \frac{3}{2}\) \(\frac{1}{4} \leq|\alpha-\beta|^2 \leq \frac{9}{4}\) \(\frac{1}{4} \leq(\alpha+\beta)^2-4 \alpha \beta \leq \frac{9}{4}\) \(\frac{1}{4} \leq \frac{25}{9}-4 \times \frac{\lambda}{4} \leq \frac{9}{4}\)…
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