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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

જો \(\theta \in\left[-\frac{7 \pi}{6}, \frac{4 \pi}{3}\right]\) હોય, તો \(\sqrt{3} \operatorname{cosec}^2 \theta-2(\sqrt{3}-1) \operatorname{cosec} \theta-4=0\) ના ઉકેલોની સંખ્યા = __________

  1. A \(6\)
  2. B \(8\)
  3. C \(10\)
  4. D \(7\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(6\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \operatorname{cosec} \theta=\frac{2(\sqrt{3}-1) \pm \sqrt{4(3+1-2 \sqrt{3})+16 \sqrt{3}}}{2 \sqrt{3}} \\ & =\frac{2(\sqrt{3-1}) \pm \sqrt{16+8 \sqrt{3}}}{2 \sqrt{3}} \\ & =\frac{2(\sqrt{3}-1) \pm(2+2 \sqrt{3})}{2 \sqrt{3}}\end{aligned}\)…
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