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JEE Mains · Maths · STD 11 - 7. binomial theoram

જો \(\left(3^{\frac{1}{2}}+5^{\frac{1}{8}}\right)^{\text {n }}\) ના વિસ્તરણમાં પૂર્ણાક પદોની સંખ્યા \(33\) હોય તો \(n\) ની ન્યૂનતમ કિમત શોધો.

  1. A \(264\)
  2. B \(256\)
  3. C \(128\)
  4. D \(248\)
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Answer & Solution

Correct Answer

(B) \(256\)

Step-by-step Solution

Detailed explanation

\(T _{ r +1}={ }^{ n } C _{ r }(3)^{\frac{ n - r }{2}}(5)^{\frac{ r }{8}} \quad( n \geq r )\) Clearly r should be a multiple of 8 . \(\because\) there are exactly 33 integral terms Possible values of \(r\) can be \(0,8,16, \ldots \ldots \ldots, 32 \times 8\) \(\therefore\) least…
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