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JEE Mains · Maths · STD 11 - 12. limits

જો \(\alpha > \beta > 0\) એ સમીકરણ \(a x^2+b x+1=0\) ના બીજ હોય, અને \(\lim _{x \rightarrow \frac{1}{\alpha}}\left(\frac{1-\cos \left(x^2+b x+a\right)}{2(1-\alpha x)^2}\right)^{\frac{1}{2}}=\frac{1}{k}\left(\frac{1}{\beta}-\frac{1}{\alpha}\right)\) હોય,તો \(k =........\)

  1. A \(2 \beta\)
  2. B \(2 \alpha\)
  3. C \(\alpha\)
  4. D \(\beta\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2 \alpha\)

Step-by-step Solution

Detailed explanation

\(\therefore a x^2+b x+1=a(x-\alpha)(x-\beta) \therefore \alpha \beta=\frac{1}{a}\) \(\therefore x^2+b x+a=a(1-\alpha x)(1-\beta x)\)…
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