JEE Mains · Maths · STD 11 - 12. limits
If \(\alpha > \beta > 0\) are the roots of the equation \(ax ^2+ bx +\) \(1=0\), and \(\lim _{x \rightarrow \frac{1}{\alpha}}\left(\frac{1-\cos \left(x^2+b x+a\right)}{2(1-\alpha x)^2}\right)^{\frac{1}{2}}=\frac{1}{k}\left(\frac{1}{\beta}-\frac{1}{\alpha}\right)\), then \(k\) is equal to
- A \(2 \beta\)
- B \(2 \alpha\)
- C \(\alpha\)
- D \(\beta\)
Answer & Solution
Correct Answer
(B) \(2 \alpha\)
Step-by-step Solution
Detailed explanation
\(\therefore a x^2+b x+1=a(x-\alpha)(x-\beta) \therefore \alpha \beta=\frac{1}{a}\) \(\therefore x^2+b x+a=a(1-\alpha x)(1-\beta x)\)…
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