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JEE Mains · Maths · STD 12 - 9. differential equations

ધારોકે \(y = y(x)\) એ વિકલ સમીકરણ \(x \frac{d y}{d x}-\sin 2 y=x^3\left(2-x^3\right) \cos ^2 y, x \neq 0\) નો ઉકેલ છે. જો \(y(2) = x\) હોય, તો \(tan(y(1))\) = ___ .

  1. A \(\frac{3}{4}\)
  2. B \(\frac{7}{4}\)
  3. C \(-\frac{7}{4}\)
  4. D \(-\frac{3}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{7}{4}\)

Step-by-step Solution

Detailed explanation

\(x \frac{d y}{d x}-\sin 2 y=x^3\left(2-x^3\right) \cos ^2 y\) \(sec^{2}y\frac{dy}{dx}-2~tan~y.\frac{1}{x}=x^{2}(2-x^{3})\) \(tan~y=t \Rightarrow sec^{2}y\frac{dy}{dx}=\frac{dt}{dx}\) \(\frac{dt}{dx}-\frac{2t}{x}=x^{2}(2-x^{3})\) (LDE) I.F.…
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