ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 11. three dimension geometry

ધારોકે રેખા \(l: x=\frac{1-y}{-2}=\frac{z-3}{\lambda}, \lambda \in R\) એ સમતલ \(P: x+2 y+3 z=4\) ને \((\alpha, \beta, \gamma)\) માં મળે છે.જો રેખા \(l\) અને સમતલ \(P\) વચ્ચેનો ખૂણો \(\cos ^{-1}\left(\sqrt{\frac{5}{14}}\right)\) હોય,તો \(\alpha+2 \beta+6 \gamma=.........\).

  1. A \(11\)
  2. B \(10\)
  3. C \(12\)
  4. D \(13\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(11\)

Step-by-step Solution

Detailed explanation

\(\ell: x =\frac{ y -1}{2}=\frac{ z -3}{\lambda}, \lambda \in R\) DR's of line \(\ell(1,2, \lambda)\) DR's of normal vector of plane \(P: x+2 y+3 z=4\) are \((1,2,3)\) Now, angle between line \(\ell\) and plane \(P\) is given by…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app