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JEE Mains · Maths · STD 11 - 8. sequence and series

ધારો કે \(S_n\) એ, સમાંતર શ્રેણી \(3,7,11, \ldots\). નાં \(n\) પદોનો સરવાળો છે. જો \(40<\left(\frac{6}{n(n+1)} \sum_{k=1}^n S_k\right)<42\) હોય, તો \(n =\) ...........

  1. A \(9\)
  2. B \(8\)
  3. C \(10\)
  4. D \(7\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(9\)

Step-by-step Solution

Detailed explanation

\(S_n= 3+7+11+............ n \) terams \({n}{2}(6+(n-1) 4)=3 n+2 n^2-2 n \) \( =2 n^2+n \) \( \sum_{k=1}^n S_k=2 \sum_{k=1}^n K^2+\sum_{k=1}^n K \) \( =2 \cdot \frac{n(n+1)(2 n+1)}{6}+\frac{n(n+1)}{2} \) \(=n(n+1)\left[\frac{2 n+1}{3}+\frac{1}{2}\right]\)…
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