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JEE Mains · Maths · STD 12 - 1. relation and function

ધારો કે \(f(x)=\left\{\begin{array}{l}x-1, x \text { is even, } \\ 2 x, x \text { is odd, }\end{array}\right.\). ને કોઈ \(\mathrm{a} \in N\) માટે, \(f(f(f(\mathrm{a})))=21\) હોય, તો  \(\lim _{x \rightarrow \mathrm{a}^{-}}\left\{\frac{|x|^3}{\mathrm{a}}-\left[\frac{x}{\mathrm{a}}\right]\right\}=\) , જ્યાં \([t]\) એ \(t\) કે તેથી નાનો મહત્તમ પૂર્ણાંક ........... દર્શાવે છે.

  1. A \(121\)
  2. B \(144\)
  3. C \(169\)
  4. D \(225\)
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Answer & Solution

Correct Answer

(B) \(144\)

Step-by-step Solution

Detailed explanation

\(f(x)=\left\{\begin{array}{cc}x-1 ; & x=\text { even } \\ 2 x ; & x=\text { odd }\end{array}\right.\) \( f(f(\mathrm{a})))=21 \) \( \text { C-1: If } a=\text { even } \) \( f(\mathrm{a})=\mathrm{a}-1=\text { odd } \) \( f(a))=2(a-1)=\text { even } \)…
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