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JEE Mains · Maths · STD 12 - 10. vector algebra

ધારો કે \(\vec{a}, \vec{b}, \vec{c}\) એ એવા ત્રણ સદિશો છે કે જેથી \(|\overrightarrow{ a }|=\sqrt{31}, \quad 4|\overrightarrow{ b }|=|\overrightarrow{ c }|=2\) અને \(2(\vec{a} \times \vec{b})=3(\vec{c} \times \vec{a})\) થાય. જો \(\vec{b}\) અને \(\vec{c}\) વચ્ચેનો ખૂણો \(\frac{2 \pi}{3}\) હોય, તો \(\left(\frac{\overrightarrow{ a } \times \overrightarrow{ c }}{\overrightarrow{ a } \cdot \overrightarrow{ b }}\right)^2=...........\).

  1. A \(6\)
  2. B \(9\)
  3. C \(12\)
  4. D \(3\)
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Correct Answer

(D) \(3\)

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Detailed explanation

\(2(\vec{a} \times \vec{b})=3(\vec{c} \times \vec{a})\) \(\vec{a} \times(2 \vec{b}+3 \vec{c})=0\) \(\vec{a}=\lambda(2 \vec{b}+3 \vec{c})\) \(|\vec{a}|^2=\lambda^2|2 \vec{b}+3 \vec{c}|^2\) \(|\vec{a}|^2=\lambda^2\left(4|\vec{b}|^2+9|\vec{c}|^2+12 \vec{b} \cdot \vec{c}\right)\)…
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