JEE Mains · Maths · STD 12 - 10. vector algebra
Let \(\vec{a}, \vec{b}, \vec{c}\) be three vectors such that \(|\overrightarrow{ a }|=\sqrt{31}, 4|\overrightarrow{ b }|=|\overrightarrow{ c }|=2\) and \(2(\overrightarrow{ a } \times \overrightarrow{ b })=3(\overrightarrow{ c } \times \overrightarrow{ a })\). If the angle between \(\vec{b}\) and \(\vec{c}\) is \(\frac{2 \pi}{3}\), then \(\left(\frac{\vec{a} \times \vec{c}}{\vec{a} \cdot \vec{b}}\right)^2\) is equal to \(............\).
- A \(6\)
- B \(9\)
- C \(12\)
- D \(3\)
Answer & Solution
Correct Answer
(D) \(3\)
Step-by-step Solution
Detailed explanation
\(2(\vec{a} \times \vec{b})=3(\vec{c} \times \vec{a})\) \(\vec{a} \times(2 \vec{b}+3 \vec{c})=0\) \(\vec{a}=\lambda(2 \vec{b}+3 \vec{c})\) \(|\vec{a}|^2=\lambda^2|2 \vec{b}+3 \vec{c}|^2\) \(|\vec{a}|^2=\lambda^2\left(4|\vec{b}|^2+9|\vec{c}|^2+12 \vec{b} \cdot \vec{c}\right)\)…
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