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JEE Mains · Maths · STD 11 - 10.1 circle and system of circle

અહી વર્તુળ \(c_{1}: x^{2}+y^{2}-2 x-\) \(6 y+\alpha=0\) નું રેખા  \(y=x+1\) ની સાપેક્ષે પ્રતિબિંબ  \(c_{2}: 5 x^{2}+5 y^{2}+10 g x+10 f y +38=0\) છે. જો \(r\) એ વર્તુળ \(c _{2}\) ત્રિજ્યા હોય તો \(\alpha+6 r^{2}\) ની કિમંત મેળવો.

  1. A \(13\)
  2. B \(11\)
  3. C \(12\)
  4. D \(10\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(12\)

Step-by-step Solution

Detailed explanation

Image of centre \(c _{1} \equiv(1,3)\) in \(x - y +1=0\) is given by \(\frac{x_{1}-1}{1}=\frac{y_{1}-3}{-1}=\frac{-2(1-3+1)}{1^{2}+1^{2}}\) \(x_{1}=2, y_{1}=2\) \(\therefore\) Centre of circle \(c _{2} \equiv(2,2)\) \(\therefore\) Equation of \(c_{2}\) be…
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