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JEE Mains · Maths · STD 11 - 8. sequence and series

અહી શ્રેઢી \(\left\{a_{n}\right\}_{n-1}^{\infty}\) એ દરેક \(n \geq 1\) માટે  \(a_{1}=1, a_{2}=1\) અને \(a_{n+2}=2 a_{n+1}+a_{n}\) આપેલ છે . તો \(47 \sum_{n=1}^{\infty} \frac{a_{n}}{2^{3 n}}\) ની કિમંત મેળવો.

  1. A \(4\)
  2. B \(7\)
  3. C \(11\)
  4. D \(9\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(7\)

Step-by-step Solution

Detailed explanation

\(a_{n+2}=2 a_{n+1}+a_{n}, \text { let } \sum_{n=1}^{\infty} \frac{a_{n}}{8^{n}}=P\) Divide by \(8^{\mathrm{n}}\) we get \(\frac{a_{n+2}}{8^{n}}=\frac{2 a_{n+1}}{8^{n}}+\frac{a_{n}}{8^{n}}\)…
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