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JEE Mains · Maths · STD 11 - 8. sequence and series

\(\left(\frac{1}{3}+\frac{4}{7}\right)+\left(\frac{1}{3^2}+\frac{1}{3} \times \frac{4}{7}+\frac{4^2}{7^2}\right)+\left(\frac{1}{3^3}+\frac{1}{3^2} \times \frac{4}{7}+\frac{1}{3} \times \frac{4^2}{7^2}+\frac{4^3}{7^3}\right)+\ldots\) અનંત પદો સુધી, બરાબર ___ છે.

  1. A \( \frac{5}{2} \)
  2. B \( \frac{7}{4} \)
  3. C \( \frac{4}{3} \)
  4. D \( \frac{6}{5} \)
Verified Solution

Answer & Solution

Correct Answer

(A) \( \frac{5}{2} \)

Step-by-step Solution

Detailed explanation

Let \(a =\frac{4}{7}, b=\frac{1}{3}\) Multiply \(N ^{ r }\) and \(D ^{ r }\) by \(( a - b )=\frac{4}{7}-\frac{1}{3}=\frac{5}{21}\) \(\frac{1}{a-b}\left[\left(a^2-b^2\right)+\left(a^3-b^3\right)+\left(a^4-b^4\right)+\ldots \infty\right]\)…
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