WBJEE · Physics · Electrostatics
Three infinite plane sheets carrying uniform charge densities \(-\sigma, 2 \sigma, 4 \sigma\) are placed parallel to \(X Z\) plane at \(Y=a, 3 a\), 4a respectively. The electric field at the point \((0,2 a, 0)\) is
- A \(\frac{5 \sigma}{2 \varepsilon_{0}} \hat{j}\)
- B \(-\frac{7 \sigma}{2 \varepsilon_{0}} \hat{j}\)
- C \(\frac{\sigma}{2 \varepsilon_{0}} \hat{j}\)
- D \(\frac{5 \sigma}{-2 \varepsilon_{0}} \hat{\mathrm{j}}\)
Answer & Solution
Correct Answer
(B) \(-\frac{7 \sigma}{2 \varepsilon_{0}} \hat{j}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{E}_{\text {net }} &=7 \mathrm{E} \\ &=7 \frac{\sigma}{2 \varepsilon_{0}} \text { alone }-\text { ve } \mathrm{Y} \text {-axis } \\ & \therefore \overrightarrow{\mathrm{E}}=-\frac{7 \sigma}{2 \varepsilon_{0}} \hat{\mathrm{j}} \end{aligned}\)
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