WBJEE · Physics · Semiconductors
In the circuit shown assume the diode to be ideal. When \(V_{i}\) increases from \(2 \mathrm{V}\) to \(6 \mathrm{V},\) the change in the current is (in mA) 
- A zero
- B 20
- C \(80 / 3\)
- D 40
Answer & Solution
Correct Answer
(B) 20
Step-by-step Solution
Detailed explanation
\(I_{\text {intitial }}=0\), \(I_{\text {final }}=\frac{3}{150}=0.02 \mathrm{A}\) So, change in \(I=0.02 \mathrm{A}=20 \mathrm{mA}\)
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