WBJEE · Physics · Electrostatics
A positive charge \(Q\) is situated at the centre of a cube. The electric flux through any face of the cube is (in SI units)
- A \(\frac{Q}{6 \varepsilon_{0}}\)
- B \(4 \pi Q\)
- C \(\frac{Q}{4 \pi \varepsilon_{0}}\)
- D \(\frac{Q}{6 \pi \varepsilon_{0}}\)
Answer & Solution
Correct Answer
(A) \(\frac{Q}{6 \varepsilon_{0}}\)
Step-by-step Solution
Detailed explanation
The positive charge \(Q\) is situated at the centre of a cube According to Gauss theorem, the flux from any closed surface \[ \phi_{E}=\frac{Q}{\varepsilon_{0}} \] Cube has 6 faces, so electric flux from any face \(\phi_{z}=\frac{Q}{6 \varepsilon_{0}}\)
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