ExamBro
ExamBro
WBJEE · Maths · Differential Equations

Let \(y(x)\) be a solution of \(\left(1+x^{2}\right) \frac{d y}{d x}+2 x y-4 x^{2}=0\) and \(y(0)=-1 .\) Then y(1) s equal to

  1. A \(\frac{1}{2}\)
  2. B \(\frac{1}{3}\)
  3. C \(\frac{1}{6}\)
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{6}\)

Step-by-step Solution

Detailed explanation

We have. \(\left(1+x^{2}\right) \frac{d y}{d x}+2 x y-4 x^{2}=0\) \(\Rightarrow \quad \frac{d y}{d x}+\left(\frac{2 x}{1+x^{2}}\right) y=\frac{4 x^{2}}{1+x^{2}}\) Here. \(\mathrm{IF}=e^{\frac{1}{1+x^{2}}}=e^{\log \left(1+x^{2}\right)}=1+x^{2}\)…
From WBJEE
Explore more questions on app