WBJEE · Physics · Nuclear Physics
In the nuclear reaction \({ }_7^{14} \mathrm{~N}+\mathrm{X} \rightarrow{ }_6^{14} \mathrm{C}+{ }_1^1 \mathrm{H}\) the \(\mathrm{X}\) will be
- A \({ }_{-1}^0 \mathrm{e}\)
- B \({ }_1^1 \mathrm{H}\)
- C \({ }_1^2 \mathrm{H}\)
- D \({ }_0^1 \mathrm{n}\)
Answer & Solution
Correct Answer
(D) \({ }_0^1 \mathrm{n}\)
Step-by-step Solution
Detailed explanation
\(\text {Hints: } \mathrm{X} \rightarrow{ }_0^1 \mathrm{n}\)
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