WBJEE · Chemistry · Thermodynamics (C)
For one mole of an ideal gas, the slope of \(V\) vs. \(T\) curve at constant pressure of 2 atm is \(X\) L \(\mathrm{mol}^{-1} \mathrm{K}^{-1} .\) The value of the ideal universal gas constant 'R' in terms of \(X\) is
- A \(X\) L atm mol \(^{-1} \mathrm{K}^{-1}\)
- B \(\frac{x}{2}\) Latm \(\mathrm{mol}^{-1} \mathrm{K}^{-1}\)
- C \(2 \times\) Latm \(\mathrm{mol}^{-1} \mathrm{K}^{-1}\)
- D \(2 X\) atm \(L^{-} \mathrm{mol}^{-1} \mathrm{K}^{-1}\)
Answer & Solution
Correct Answer
(C) \(2 \times\) Latm \(\mathrm{mol}^{-1} \mathrm{K}^{-1}\)
Step-by-step Solution
Detailed explanation
Ideal gas equation is \[ p V=n R T \quad \text { or } \quad V=\frac{n R T}{p}+C \] or \(\quad V=\frac{R T}{p}+0 \quad\) (for \(1 \mathrm{mol}\) ) When \(V\) vs \(T\) is plotted, a straight line is obtained, slope of which is given by \(R / p\). Thus.…
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