WBJEE · Physics · Laws of Motion
A metallic block of mass \(20 \mathrm{~kg}\) is dragged with a uniform velocity of \(0.5 \mathrm{~ms}^{-1}\) on a horizontal table for \(2.1 \mathrm{~s}\). The co-efficient of static friction between the block and the table is \(0.10\). What will be the maximum possible rise in temperature of the metal block if the specific heat of the block is \(0.1\) C.G.S unit ? Assume \(g=10 \mathrm{~ms}^{-2}\) uniform rise in temperature throughout the whole block. [lgnore absorption of heat by the table]
- A \(0.0025^{\circ} \mathrm{C}\)
- B \(0.025^{\circ} \mathrm{C}\)
- C \(0.001^{\circ} \mathrm{C}\)
- D \(0.05^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(A) \(0.0025^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Hint: friction \(f=\mu \mathrm{mg}=0.1 \times 20 \times 10=20\) \(\mathrm{~W}_{\mathrm{f}}=\) heat \(\Rightarrow(\mathrm{f.u}) \mathrm{t}=\mathrm{mc} \Delta \mathrm{T}\) \(\Rightarrow 20 \times 0.5 \times 2.1=20 \times 0.1 \times 4.2 \times 10^{3} . \Delta \mathrm{T}\)…
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