WBJEE · Physics · Experimental Physics
If \(x_1\) be the size of the magnified image and \(x_2\) the size of the diminished image in Lens Displacement Method, then the size of the object is :
- A \(\sqrt{x_1 x_2}\)
- B \(x_1 x_2\)
- C \(x_1^2 x_2\)
- D \(x_1 x_2^2\)
Answer & Solution
Correct Answer
(A) \(\sqrt{x_1 x_2}\)
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