WBJEE · Chemistry · Some Basic Concepts of Chemistry
In a flask, the weight ratio of \(\mathrm{CH}_{4}(g)\) and \(\mathrm{SO}_{2}(g)\) at \(298 \mathrm{K}\) and 1 bar is \(1: 2 .\) The ratio of the number of molecules of \(\mathrm{SO}_{2}(\mathrm{g})\) and \(\mathrm{CH}_{4}(g)\) is
- A \(1 : 4\)
- B \(4 : 1\)
- C \(1 : 2\)
- D \(2 : 1\)
Answer & Solution
Correct Answer
(C) \(1 : 2\)
Step-by-step Solution
Detailed explanation
Given, weight ratio : \(W_{\mathrm{C H_{4}},}: W_{\mathrm{SO}_{2}}=1: 2\) \(\because \quad n=\frac{w}{m} \quad\left[\begin{array}{l}n=\text { no. of mole } \\ w=\text { mass } \\ M=\text { molar mas: }\end{array}\right.\)…
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