WBJEE · Physics · Laws of Motion
A mass of \(1 \mathrm{kg}\) is suspended by means of a thread. The system is
(i) lifted up with an acceleration of \(4.9 \mathrm{ms}^{-2}\)
(ii) lowered with an acceleration of \(4.9 \mathrm{ms}^{-2}\). The ratio of tension in the first and second case is
- A 3: 1
- B 1: 2
- C 1: 3
- D 2: 1
Answer & Solution
Correct Answer
(A) 3: 1
Step-by-step Solution
Detailed explanation
When the body of mass m lifted up the forces acting on the body \[ \begin{aligned} T_{1}-m g &=\frac{m g}{2} \\ T_{1} &=m g+\frac{m g}{2}=\frac{3 m g}{2} \end{aligned} \] (ii) When the body lowered the acting forces \[ \left(m g-T_{2}\right)=\frac{m g}{2} \]…
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